There is an EASY way, and a FORMAL way to draw the Lewis structure of CF_4,carbon tetrafluoride:

Formal Way

In the formal way we find how many electrons we have (step 1), how many each atom needs (step 2), how many of those are bonding (step 3 & 4), and how many are lone pairs (step 5). This info can then be used to determine the Lewis Dot Structure.

The total number of electrons present in the valence shell of an atom is called valence electrons, and there are a total of seven electrons present in the valence shell of fluorine (2s22p5). Thus, fluorine has seven valence electrons.
Since valence electrons are the ones which are contained in the outermost shell of the atom, Fluorine has 7 valence electrons. By each contributing one electron, they make the following molecule: In this molecule, the hydrogen atom does not have nonbonding electrons, while the fluorine atom has six nonbonding electrons (three lone electron pairs).
Fluorine is a halogen. All halogens have 7 valence electrons. There are thus 7 valence electrons for Fluorine, 2 in the 2s orbital, and 5 in the 2p orbitals.
Fluorine has 7 Valence electrons. Valence electrons are those electrons which are present in the outermost shell of an atom. Fluorine has atomic number 9. Atomic number is the number of protons present in the nucleus of an atom.

Fluorine, the most reactive chemical element and the lightest member of the halogen elements. Its chemical activity can be attributed to its extreme ability to attract electrons (it is the most electronegative element) and to the small size of its atoms.

Step 1: Find valence e- for all atoms. Add them together.

C: 4
F: 7×4 =28

Total=32

Step 2: Find octet e- for each atom and add them together.

C: 8
F: 8×4=32

Total=40

Step 3: Find the bonding e-. Subtract step 1 total from step 2

Fluorine # Of Valence Electrons

40-32=8e-

Step 4: Find number of bonds by dividing the number of bonding electrons by
2 (because each bond is made of 2 e-)

Number Of Valence Electrons List

8e-/2 = 4 bonds

Step 5: The rest are nonbonding pairs. Subtract bonding electrons (step 3) from valence electrons (step 1).

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32-8= 24e-= 12 lone pairs

Use information from step 4 and 5 to draw the CF₄lewis structure.

Easy Way – Treat them like Puzzle Pieces

Lewis structure of CF₄

Alternatively a dot method can be used to draw the CF₄ Lewis structure.

Calculate the total valence electrons in the molecule.
C: 4
F: 7×4=28

Total=32

Remember that uncharged carbon has 4 bonds and no lone pairs and fluorine has one bond and three lone pairs.

Fluorine total number of valence electrons

Put carbon in center and arrange fluorine atoms on the sides. Arrange electrons until carbon gets 8 electrons, and each fluorine gets 8 (via one bond and three lone pairs).

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A brief closing summary: The Lewis structure is used to represent bonding in a molecule, whether that be covalent or ionic. Covalent bonds are formed by sharing electrons between the atoms and are stronger than ionic bonds, which are much more of an electrostatic interactions. Most Lewis structures you encounter will be covalent bonds. Ferroelectric fet. Most Lewis structures will follow the octet rule, which states that the outer (valence) shell is stable when it has eight electrons. There are MANY exceptions to this rule, but it should be used as a general guide for creating Lewis structures.

Formal Way

Fluorine # Of Valence Electrons

Number Of Valence Electrons List

Easy Way – Treat them like Puzzle Pieces

Lewis structure of CF4

Want a free lesson on the essentials to know for general chemistry class? Click here to get it.

Lewis structure of CF₄

Fluorine Number Of Valence Electrons